I have added numbers to make you understand how we will create this pattern using for loop
- As we know we first see how many lines of code needs to be printed, in this case it is 9
- Since we will take user input it can be simply n which will be taken from user
- So now we know i will iterate from 1 to n
- In this simple pattern the number of times the symbol is printed is same as n i.e 9
- So j will also iterate from 1 to n
- Remember to use \n to move to next line
Code
#include<stdio.h>
#include<conio.h>
void main(){
int i,j,n;
clrscr();
printf("Enter number of lines ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
printf("*");
}
printf("\n");
}
getch();
}
Note: scanf is used for taking user input
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