6.Inverted triangle pattern with left spacing

 

I have added numbers to make you understand how we will create this pattern using for loop

• As we know we first see how many lines of code needs to be printed, in this case it is 9 so i will iterate from 1 to n
• Since we will take user input it can be simply n which will be taken from user
• Here there is a difference that only stars are not being printed
• Along with the stars space is also being printed
• Inside outer i for loop there will be two loops one for star and another for space
• For space we will use variable s
• As we can see for i =1 there is no space,for i=2 there is 1 space and so on
• So we can say that s will iterate from 1 to i-1
• As for the pattern as we have seen before
• j will iterate from i to n

Code

#include<stdio.h>

#include<conio.h>

void main(){

int i,j,n,s;

clrscr();

printf("Enter number of lines ");

scanf("%d",&n);

for(i=1;i<=n;i++)

    {

          for(s=1;s<=i-1;s++)

               {

                printf(" ");

                 }

          for(j=i;j<=n;j++)

               {

                 printf("*");   

                   }

           printf("\n");

     }

getch();

}

Note: scanf is used for taking user input

5.Inverted Triangle

             

I have added numbers to make you understand how we will create this pattern using for loop

• As we know we first see how many lines of code needs to be printed, in this case it is 9
• Since we will take user input it can be simply n which will be taken from user
• For the inner loop we will look how many times the stars are printing
• If we observe carefully we can see that for each line 
• Stars are printing from i to n
• For i=1 , the stars are printing from 1to n i.e 9 from our example
• For i=4 , the stars are printing from 4 to n i.e 6  from our example
• So for the inner loop j will iterate from i to n
• Remember to print "\n" to make it move to next line

Code

#include<stdio.h>

#include<conio.h>

void main(){

int i,j,n;

clrscr();

printf("Enter number of lines ");

scanf("%d",&n);

for(i=1;i<=n;i++)

    {

          for(j=i;j<=n;j++)

               {

                 printf("*");   

                   }

           printf("\n");

     }

getch();

}

Note: scanf is used for taking user input

 

4.Triangle pattern with left spacing

 

I have added numbers to make you understand how we will create this pattern using for loop

• As we know we first see how many lines of code needs to be printed, in this case it is 9
• Since we will take user input it can be simply n which will be taken from user
• Here there is a difference that only stars are not being printed
• Along with the stars space is also being printed
• Inside outer i for loop there will be two loops one for star and another for space
• For space we will use variable s
• For i=1 ,the number of space is 8,for i=4 it is 5
• Here we can see space is being printed n-i times
• So s will iterate from from 1 to n-i
• As we can see for each line the stars printed are same as i's value
• For i=1, stars printed is 1,for i=n it is n
• So j loop that will decide what needs to be printed will iterate from 1 to i
• Remember to print "\n" to make it move to next line

Code

#include<stdio.h>

#include<conio.h>

void main(){

int i,j,n,s;

clrscr();

printf("Enter number of lines ");

scanf("%d",&n);

for(i=1;i<=n;i++)

    {    for(s=1;s<=n-i;s++)

                {

                   printf(" ");

                  }

          for(j=1;j<=i;j++)

               {

                 printf("*");   

                   }

           printf("\n");

     }

getch();

}

Note: scanf is used for taking user input,s is for space , j for pattern

3.Triangle pattern

 

I have added numbers to make you understand how we will create this pattern using for loop

• As we know we first see how many lines of code needs to be printed, in this case it is 9
• Since we will take user input it can be simply n which will be taken from user
• As we can see for each line the stars printed are same as i's value
• For i=1, stars printed is 1,for i=n it is n
• So j loop that will decide what needs to be printed will iterate from 1 to i
• Remember to print "\n" to make it move to next line

Code

#include<stdio.h>

#include<conio.h>

void main(){

int i,j,n;

clrscr();

printf("Enter number of lines ");

scanf("%d",&n);

for(i=1;i<=n;i++)

    {

          for(j=1;j<=i;j++)

               {

                 printf("*");   

                   }

           printf("\n");

     }

getch();

}

Note: scanf is used for taking user input

2.Rectangle pattern

 

I have added numbers to make you understand how we will create this pattern using for loop

• As we know we first see how many lines of code needs to be printed, in this case it is 9 so i will iterate from 1 to n
• Since we will take user input it can be simply n which will be taken from user
• In this example each time stars are being printed 15 times , let that be m
• It will also be taken from user
• So j loop will iterate from 1 to m

Code

#include<stdio.h>

#include<conio.h>

void main(){

int i,j,n,m;

clrscr();

printf("Enter number of lines ");

scanf("%d",&n);

printf("Enter number of lines ");

scanf("%d",&m);

for(i=1;i<=n;i++)

    {

          for(j=1;j<=m;j++)

               {

                 printf("*");   

                   }

           printf("\n");

     }

getch();

}

Note: scanf is used for taking user input

1.Square Pattern

I have added numbers to make you understand how we will create this pattern using for loop

• As we know we first see how many lines of code needs to be printed, in this case it is 9
• Since we will take user input it can be simply n which will be taken from user
• So now we know i will iterate from 1 to n
• In this simple pattern the number of times the symbol is printed is same as n i.e 9
• So j will also iterate from 1 to n
• Remember to use \n to move to next line

Code

#include<stdio.h>

#include<conio.h>

void main(){

int i,j,n;

clrscr();

printf("Enter number of lines ");

scanf("%d",&n);

for(i=1;i<=n;i++)

    {

          for(j=1;j<=n;j++)

               {

                 printf("*");   

                   }

           printf("\n");

     }

getch();

}

Note: scanf is used for taking user input